Base | Representation |
---|---|
bin | 11001101110010000100001… |
… | …100110011011110110001100 |
3 | 112211120010022101002011121022 |
4 | 121232100201212123312030 |
5 | 104312010221042102200 |
6 | 1040335112223453312 |
7 | 32554241630221466 |
oct | 3156204146336614 |
9 | 484503271064538 |
10 | 113130002300300 |
11 | 3305718a007277 |
12 | 10831428a57238 |
13 | 4b181622ccbbb |
14 | 1dd1742741136 |
15 | d12b870c1885 |
hex | 66e42199bd8c |
113130002300300 has 72 divisors (see below), whose sum is σ = 245934081471792. Its totient is φ = 45170594784000.
The previous prime is 113130002300221. The next prime is 113130002300309. The reversal of 113130002300300 is 3003200031311.
It is not an unprimeable number, because it can be changed into a prime (113130002300309) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 141058430 + ... + 141858170.
Almost surely, 2113130002300300 is an apocalyptic number.
113130002300300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113130002300300 is an abundant number, since it is smaller than the sum of its proper divisors (132804079171492).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113130002300300 is a wasteful number, since it uses less digits than its factorization.
113130002300300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 802299 (or 802292 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 113130002300300 its reverse (3003200031311), we get a palindrome (116133202331611).
The spelling of 113130002300300 in words is "one hundred thirteen trillion, one hundred thirty billion, two million, three hundred thousand, three hundred".
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