Base | Representation |
---|---|
bin | 1010010010100000001101… |
… | …1011100101101001100010 |
3 | 1111001111211112001100022211 |
4 | 2210220003123211221202 |
5 | 2440323011330441120 |
6 | 40021042054152334 |
7 | 2245223502313453 |
oct | 244500333455142 |
9 | 44044745040284 |
10 | 11313001421410 |
11 | 36718a9411587 |
12 | 13286513526aa |
13 | 640a71a01610 |
14 | 2b17a32d312a |
15 | 14942549b25a |
hex | a4a036e5a62 |
11313001421410 has 32 divisors (see below), whose sum is σ = 22686018773040. Its totient is φ = 4033070001408.
The previous prime is 11313001421383. The next prime is 11313001421443. The reversal of 11313001421410 is 1412410031311.
It can be written as a sum of positive squares in 8 ways, for example, as 6771793539289 + 4541207882121 = 2602267^2 + 2131011^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1500394297 + ... + 1500401836.
Almost surely, 211313001421410 is an apocalyptic number.
11313001421410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11313001421410 is an abundant number, since it is smaller than the sum of its proper divisors (11373017351630).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11313001421410 is a wasteful number, since it uses less digits than its factorization.
11313001421410 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3000796182.
The product of its (nonzero) digits is 288, while the sum is 22.
Adding to 11313001421410 its reverse (1412410031311), we get a palindrome (12725411452721).
The spelling of 11313001421410 in words is "eleven trillion, three hundred thirteen billion, one million, four hundred twenty-one thousand, four hundred ten".
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