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11313020302151 is a prime number
BaseRepresentation
bin1010010010100000010010…
…0011100111001101000111
31111001111212211120120211112
42210220010203213031013
52440323031144132101
640021044010555235
72245224121641401
oct244500443471507
944044784516745
1011313020302151
1136719090379a7
121328657738b1b
13640a758b2459
142b17a5a09b71
15149426e7a6bb
hexa4a048e7347

11313020302151 has 2 divisors, whose sum is σ = 11313020302152. Its totient is φ = 11313020302150.

The previous prime is 11313020302139. The next prime is 11313020302261. The reversal of 11313020302151 is 15120302031311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11313020302151 - 210 = 11313020301127 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11313020382151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656510151075 + 5656510151076.

It is an arithmetic number, because the mean of its divisors is an integer number (5656510151076).

Almost surely, 211313020302151 is an apocalyptic number.

11313020302151 is a deficient number, since it is larger than the sum of its proper divisors (1).

11313020302151 is an equidigital number, since it uses as much as digits as its factorization.

11313020302151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 23.

Adding to 11313020302151 its reverse (15120302031311), we get a palindrome (26433322333462).

The spelling of 11313020302151 in words is "eleven trillion, three hundred thirteen billion, twenty million, three hundred two thousand, one hundred fifty-one".