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11313020302513 is a prime number
BaseRepresentation
bin1010010010100000010010…
…0011100111010010110001
31111001111212211120121022221
42210220010203213102301
52440323031144140023
640021044011001041
72245224121642426
oct244500443472261
944044784517287
1011313020302513
1136719090381a6
121328657739181
13640a758b2677
142b17a5a09d4d
15149426e7a85d
hexa4a048e74b1

11313020302513 has 2 divisors, whose sum is σ = 11313020302514. Its totient is φ = 11313020302512.

The previous prime is 11313020302489. The next prime is 11313020302523. The reversal of 11313020302513 is 31520302031311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8109321249969 + 3203699052544 = 2847687^2 + 1789888^2 .

It is an emirp because it is prime and its reverse (31520302031311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11313020302513 is a prime.

It is not a weakly prime, because it can be changed into another prime (11313020302523) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656510151256 + 5656510151257.

It is an arithmetic number, because the mean of its divisors is an integer number (5656510151257).

Almost surely, 211313020302513 is an apocalyptic number.

It is an amenable number.

11313020302513 is a deficient number, since it is larger than the sum of its proper divisors (1).

11313020302513 is an equidigital number, since it uses as much as digits as its factorization.

11313020302513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 11313020302513 its reverse (31520302031311), we get a palindrome (42833322333824).

The spelling of 11313020302513 in words is "eleven trillion, three hundred thirteen billion, twenty million, three hundred two thousand, five hundred thirteen".