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11313030101100 = 2235271319375997103
BaseRepresentation
bin1010010010100000010100…
…1000111111100001101100
31111001111220112000102110120
42210220011020333201230
52440323041201213400
640021045001004540
72245224301142640
oct244500510774154
944044815012416
1011313030101100
113671913620002
12132865aa83750
13640a77933650
142b17a703ac20
15149427c63ca0
hexa4a0523f86c

11313030101100 has 2304 divisors, whose sum is σ = 45181641523200. Its totient is φ = 2119809761280.

The previous prime is 11313030101053. The next prime is 11313030101101. The reversal of 11313030101100 is 110103031311.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 11313030101100.

It is not an unprimeable number, because it can be changed into a prime (11313030101101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 767 ways as a sum of consecutive naturals, for example, 109835243649 + ... + 109835243751.

Almost surely, 211313030101100 is an apocalyptic number.

11313030101100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11313030101100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22590820761600).

11313030101100 is an abundant number, since it is smaller than the sum of its proper divisors (33868611422100).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11313030101100 is a wasteful number, since it uses less digits than its factorization.

11313030101100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 352 (or 345 counting only the distinct ones).

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 11313030101100 its reverse (110103031311), we get a palindrome (11423133132411).

The spelling of 11313030101100 in words is "eleven trillion, three hundred thirteen billion, thirty million, one hundred one thousand, one hundred".