Search a number
-
+
1131304343536 = 2470706521471
BaseRepresentation
bin10000011101100110111…
…111100101011111110000
311000011002112201012001201
4100131212333211133300
5122013402402443121
62223414122140544
7144506530154143
oct20354677453760
94004075635051
101131304343536
113a6868899694
12163307651754
13828b2469383
143ca80c4405a
151e663d76e91
hex10766fe57f0

1131304343536 has 10 divisors (see below), whose sum is σ = 2191902165632. Its totient is φ = 565652171760.

The previous prime is 1131304343497. The next prime is 1131304343539. The reversal of 1131304343536 is 6353434031311.

It is a junction number, because it is equal to n+sod(n) for n = 1131304343495 and 1131304343504.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131304343539) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35353260720 + ... + 35353260751.

Almost surely, 21131304343536 is an apocalyptic number.

1131304343536 is a gapful number since it is divisible by the number (16) formed by its first and last digit.

It is an amenable number.

1131304343536 is a deficient number, since it is larger than the sum of its proper divisors (1060597822096).

1131304343536 is an equidigital number, since it uses as much as digits as its factorization.

1131304343536 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70706521479 (or 70706521473 counting only the distinct ones).

The product of its (nonzero) digits is 116640, while the sum is 37.

Adding to 1131304343536 its reverse (6353434031311), we get a palindrome (7484738374847).

The spelling of 1131304343536 in words is "one trillion, one hundred thirty-one billion, three hundred four million, three hundred forty-three thousand, five hundred thirty-six".

Divisors: 1 2 4 8 16 70706521471 141413042942 282826085884 565652171768 1131304343536