Base | Representation |
---|---|
bin | 1010010010100000011000… |
… | …0100010111100010010101 |
3 | 1111001111221121022012102011 |
4 | 2210220012010113202111 |
5 | 2440323104142302231 |
6 | 40021050314344221 |
7 | 2245224550350325 |
oct | 244500604274225 |
9 | 44044847265364 |
10 | 11313045665941 |
11 | 3671921391108 |
12 | 132866412b071 |
13 | 640a7ac23106 |
14 | 2b17a912d285 |
15 | 1494292da9b1 |
hex | a4a06117895 |
11313045665941 has 2 divisors, whose sum is σ = 11313045665942. Its totient is φ = 11313045665940.
The previous prime is 11313045665917. The next prime is 11313045665947. The reversal of 11313045665941 is 14956654031311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8332170902500 + 2980874763441 = 2886550^2 + 1726521^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11313045665941 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11313045665947) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656522832970 + 5656522832971.
It is an arithmetic number, because the mean of its divisors is an integer number (5656522832971).
Almost surely, 211313045665941 is an apocalyptic number.
It is an amenable number.
11313045665941 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313045665941 is an equidigital number, since it uses as much as digits as its factorization.
11313045665941 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1166400, while the sum is 49.
The spelling of 11313045665941 in words is "eleven trillion, three hundred thirteen billion, forty-five million, six hundred sixty-five thousand, nine hundred forty-one".
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