Base | Representation |
---|---|
bin | 10101000100100111… |
… | …11000010101100001 |
3 | 1002012102111202001202 |
4 | 22202103320111201 |
5 | 141132120230243 |
6 | 5110330010545 |
7 | 550230244565 |
oct | 124223702541 |
9 | 32172452052 |
10 | 11313055073 |
11 | 4885a197a1 |
12 | 2238876a55 |
13 | 10b3a46738 |
14 | 7946c16a5 |
15 | 4632cb4b8 |
hex | 2a24f8561 |
11313055073 has 2 divisors, whose sum is σ = 11313055074. Its totient is φ = 11313055072.
The previous prime is 11313055037. The next prime is 11313055097. The reversal of 11313055073 is 37055031311.
It is a happy number.
Together with previous prime (11313055037) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8579020129 + 2734034944 = 92623^2 + 52288^2 .
It is a cyclic number.
It is not a de Polignac number, because 11313055073 - 28 = 11313054817 is a prime.
It is not a weakly prime, because it can be changed into another prime (11313055673) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656527536 + 5656527537.
It is an arithmetic number, because the mean of its divisors is an integer number (5656527537).
Almost surely, 211313055073 is an apocalyptic number.
It is an amenable number.
11313055073 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313055073 is an equidigital number, since it uses as much as digits as its factorization.
11313055073 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4725, while the sum is 29.
Adding to 11313055073 its reverse (37055031311), we get a palindrome (48368086384).
The spelling of 11313055073 in words is "eleven billion, three hundred thirteen million, fifty-five thousand, seventy-three".
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