Search a number
-
+
113130803 is a prime number
BaseRepresentation
bin1101011111000…
…11110100110011
321212212122021202
412233203310303
5212430141203
615120441415
72542411262
oct657436463
9255778252
10113130803
115894a935
1231a7926b
131a590406
141104c5d9
159dea388
hex6be3d33

113130803 has 2 divisors, whose sum is σ = 113130804. Its totient is φ = 113130802.

The previous prime is 113130781. The next prime is 113130817. The reversal of 113130803 is 308031311.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 113130803 - 212 = 113126707 is a prime.

It is a super-4 number, since 4×1131308034 (a number of 33 digits) contains 4444 as substring.

It is a Chen prime.

It is a weakly prime.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56565401 + 56565402.

It is an arithmetic number, because the mean of its divisors is an integer number (56565402).

Almost surely, 2113130803 is an apocalyptic number.

113130803 is a deficient number, since it is larger than the sum of its proper divisors (1).

113130803 is an equidigital number, since it uses as much as digits as its factorization.

113130803 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 20.

The square root of 113130803 is about 10636.2964889100. The cubic root of 113130803 is about 483.6452831491.

The spelling of 113130803 in words is "one hundred thirteen million, one hundred thirty thousand, eight hundred three".