Base | Representation |
---|---|
bin | 10101000100101000… |
… | …01000001100000000 |
3 | 1002012102122001010110 |
4 | 22202110020030000 |
5 | 141132124320000 |
6 | 5110331231320 |
7 | 550230635100 |
oct | 124224101400 |
9 | 32172561113 |
10 | 11313120000 |
11 | 4885a63556 |
12 | 22388a8540 |
13 | 10b3a6a160 |
14 | 7946db200 |
15 | 4632e0850 |
hex | 2a2508300 |
11313120000 has 1080 divisors, whose sum is σ = 48408141936. Its totient is φ = 2322432000.
The previous prime is 11313119977. The next prime is 11313120017. The reversal of 11313120000 is 2131311.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 119 ways as a sum of consecutive naturals, for example, 305759982 + ... + 305760018.
Almost surely, 211313120000 is an apocalyptic number.
11313120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11313120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (24204070968).
11313120000 is an abundant number, since it is smaller than the sum of its proper divisors (37095021936).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11313120000 is an equidigital number, since it uses as much as digits as its factorization.
11313120000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 103 (or 67 counting only the distinct ones).
The product of its (nonzero) digits is 18, while the sum is 12.
Adding to 11313120000 its reverse (2131311), we get a palindrome (11315251311).
The spelling of 11313120000 in words is "eleven billion, three hundred thirteen million, one hundred twenty thousand".
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