Base | Representation |
---|---|
bin | 10000011101100111011… |
… | …101010011010001100110 |
3 | 11000011010002100221111121 |
4 | 100131213131103101212 |
5 | 122013411401230342 |
6 | 2223415001124154 |
7 | 144506653316455 |
oct | 20354735232146 |
9 | 4004102327447 |
10 | 1131312133222 |
11 | 3a687222a147 |
12 | 16330a18965a |
13 | 828b3c65b5b |
14 | 3ca81cb0b9c |
15 | 1e6648b5067 |
hex | 10767753466 |
1131312133222 has 4 divisors (see below), whose sum is σ = 1696968199836. Its totient is φ = 565656066610.
The previous prime is 1131312133213. The next prime is 1131312133277. The reversal of 1131312133222 is 2223312131311.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×11313121332222 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 282828033304 + ... + 282828033307.
It is an arithmetic number, because the mean of its divisors is an integer number (424242049959).
Almost surely, 21131312133222 is an apocalyptic number.
1131312133222 is a deficient number, since it is larger than the sum of its proper divisors (565656066614).
1131312133222 is an equidigital number, since it uses as much as digits as its factorization.
1131312133222 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 565656066613.
The product of its digits is 1296, while the sum is 25.
Adding to 1131312133222 its reverse (2223312131311), we get a palindrome (3354624264533).
The spelling of 1131312133222 in words is "one trillion, one hundred thirty-one billion, three hundred twelve million, one hundred thirty-three thousand, two hundred twenty-two".
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