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1131313031969 is a prime number
BaseRepresentation
bin10000011101100111100…
…000101110101100100001
311000011010011001121100112
4100131213200232230201
5122013412114010334
62223415032301105
7144506664051641
oct20354740565441
94004104047315
101131313031969
113a687279340a
1216330a541795
13828b41bbc63
143ca82066521
151e6649e14ce
hex1076782eb21

1131313031969 has 2 divisors, whose sum is σ = 1131313031970. Its totient is φ = 1131313031968.

The previous prime is 1131313031929. The next prime is 1131313031977. The reversal of 1131313031969 is 9691303131311.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 601020315025 + 530292716944 = 775255^2 + 728212^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1131313031969 is a prime.

It is a super-2 number, since 2×11313130319692 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1131313031929) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565656515984 + 565656515985.

It is an arithmetic number, because the mean of its divisors is an integer number (565656515985).

Almost surely, 21131313031969 is an apocalyptic number.

It is an amenable number.

1131313031969 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131313031969 is an equidigital number, since it uses as much as digits as its factorization.

1131313031969 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 39366, while the sum is 41.

The spelling of 1131313031969 in words is "one trillion, one hundred thirty-one billion, three hundred thirteen million, thirty-one thousand, nine hundred sixty-nine".