Base | Representation |
---|---|
bin | 10000011101100111100… |
… | …000101110101100111001 |
3 | 11000011010011001121101102 |
4 | 100131213200232230321 |
5 | 122013412114010433 |
6 | 2223415032301145 |
7 | 144506664052004 |
oct | 20354740565471 |
9 | 4004104047342 |
10 | 1131313031993 |
11 | 3a6872793431 |
12 | 16330a5417b5 |
13 | 828b41bbc81 |
14 | 3ca8206653b |
15 | 1e6649e14e8 |
hex | 1076782eb39 |
1131313031993 has 2 divisors, whose sum is σ = 1131313031994. Its totient is φ = 1131313031992.
The previous prime is 1131313031977. The next prime is 1131313032001. The reversal of 1131313031993 is 3991303131311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 862292388409 + 269020643584 = 928597^2 + 518672^2 .
It is a cyclic number.
It is not a de Polignac number, because 1131313031993 - 24 = 1131313031977 is a prime.
It is not a weakly prime, because it can be changed into another prime (1131313031903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565656515996 + 565656515997.
It is an arithmetic number, because the mean of its divisors is an integer number (565656515997).
Almost surely, 21131313031993 is an apocalyptic number.
It is an amenable number.
1131313031993 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131313031993 is an equidigital number, since it uses as much as digits as its factorization.
1131313031993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19683, while the sum is 38.
The spelling of 1131313031993 in words is "one trillion, one hundred thirty-one billion, three hundred thirteen million, thirty-one thousand, nine hundred ninety-three".
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