Base | Representation |
---|---|
bin | 11001101110010001101111… |
… | …100010111010111110110111 |
3 | 112211120020200111202022020102 |
4 | 121232101233202322332313 |
5 | 104312020410330031403 |
6 | 1040335450100224315 |
7 | 32554316216420261 |
oct | 3156215742727667 |
9 | 484506614668212 |
10 | 113131310002103 |
11 | 330577a0194a68 |
12 | 1083173299b09b |
13 | 4b18310203653 |
14 | 1dd18282a8b31 |
15 | d12c11cd3b88 |
hex | 66e46f8bafb7 |
113131310002103 has 2 divisors, whose sum is σ = 113131310002104. Its totient is φ = 113131310002102.
The previous prime is 113131310002093. The next prime is 113131310002127. The reversal of 113131310002103 is 301200013131311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113131310002103 - 28 = 113131310001847 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113131310002303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56565655001051 + 56565655001052.
It is an arithmetic number, because the mean of its divisors is an integer number (56565655001052).
Almost surely, 2113131310002103 is an apocalyptic number.
113131310002103 is a deficient number, since it is larger than the sum of its proper divisors (1).
113131310002103 is an equidigital number, since it uses as much as digits as its factorization.
113131310002103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 113131310002103 its reverse (301200013131311), we get a palindrome (414331323133414).
The spelling of 113131310002103 in words is "one hundred thirteen trillion, one hundred thirty-one billion, three hundred ten million, two thousand, one hundred three".
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