Base | Representation |
---|---|
bin | 110100101011100101… |
… | …0000010110010100001 |
3 | 101211000022200121002221 |
4 | 1221113022002302201 |
5 | 3323143114302403 |
6 | 123545530311041 |
7 | 11113334015356 |
oct | 1512712026241 |
9 | 354008617087 |
10 | 113131400353 |
11 | 43a847a9594 |
12 | 19b13588481 |
13 | a88c19a41a |
14 | 569303262d |
15 | 2e21e94dbd |
hex | 1a57282ca1 |
113131400353 has 2 divisors, whose sum is σ = 113131400354. Its totient is φ = 113131400352.
The previous prime is 113131400297. The next prime is 113131400377. The reversal of 113131400353 is 353004131311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 113129977104 + 1423249 = 336348^2 + 1193^2 .
It is a cyclic number.
It is not a de Polignac number, because 113131400353 - 213 = 113131392161 is a prime.
It is not a weakly prime, because it can be changed into another prime (113131400383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56565700176 + 56565700177.
It is an arithmetic number, because the mean of its divisors is an integer number (56565700177).
Almost surely, 2113131400353 is an apocalyptic number.
It is an amenable number.
113131400353 is a deficient number, since it is larger than the sum of its proper divisors (1).
113131400353 is an equidigital number, since it uses as much as digits as its factorization.
113131400353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1620, while the sum is 25.
Adding to 113131400353 its reverse (353004131311), we get a palindrome (466135531664).
The spelling of 113131400353 in words is "one hundred thirteen billion, one hundred thirty-one million, four hundred thousand, three hundred fifty-three".
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