Base | Representation |
---|---|
bin | 10000011101100111100… |
… | …101001100100000000111 |
3 | 11000011010020021002012101 |
4 | 100131213211030200013 |
5 | 122013412413441011 |
6 | 2223415113332531 |
7 | 144510010025644 |
oct | 20354745144007 |
9 | 4004106232171 |
10 | 1131314202631 |
11 | 3a68734129a8 |
12 | 16330aa07147 |
13 | 828b450ba62 |
14 | 3ca8228cdcb |
15 | 1e664b732c1 |
hex | 1076794c807 |
1131314202631 has 2 divisors, whose sum is σ = 1131314202632. Its totient is φ = 1131314202630.
The previous prime is 1131314202583. The next prime is 1131314202677. The reversal of 1131314202631 is 1362024131311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1131314202631 - 219 = 1131313678343 is a prime.
It is a super-2 number, since 2×11313142026312 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1131314202631.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131314200631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565657101315 + 565657101316.
It is an arithmetic number, because the mean of its divisors is an integer number (565657101316).
Almost surely, 21131314202631 is an apocalyptic number.
1131314202631 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131314202631 is an equidigital number, since it uses as much as digits as its factorization.
1131314202631 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 28.
Adding to 1131314202631 its reverse (1362024131311), we get a palindrome (2493338333942).
The spelling of 1131314202631 in words is "one trillion, one hundred thirty-one billion, three hundred fourteen million, two hundred two thousand, six hundred thirty-one".
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