Base | Representation |
---|---|
bin | 10000011101100111100… |
… | …110010110001011111000 |
3 | 11000011010020211102012111 |
4 | 100131213212112023320 |
5 | 122013413003120230 |
6 | 2223415124022104 |
7 | 144510012423601 |
oct | 20354746261370 |
9 | 4004106742174 |
10 | 1131314504440 |
11 | 3a68735a972a |
12 | 16330ab31934 |
13 | 828b45b6243 |
14 | 3ca8232ada8 |
15 | 1e664bd292a |
hex | 107679962f8 |
1131314504440 has 16 divisors (see below), whose sum is σ = 2545457635080. Its totient is φ = 452525801760.
The previous prime is 1131314504417. The next prime is 1131314504447. The reversal of 1131314504440 is 444054131311.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1131314504447) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14141431266 + ... + 14141431345.
Almost surely, 21131314504440 is an apocalyptic number.
1131314504440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1131314504440 is an abundant number, since it is smaller than the sum of its proper divisors (1414143130640).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1131314504440 is a wasteful number, since it uses less digits than its factorization.
1131314504440 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28282862622 (or 28282862618 counting only the distinct ones).
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 1131314504440 its reverse (444054131311), we get a palindrome (1575368635751).
The spelling of 1131314504440 in words is "one trillion, one hundred thirty-one billion, three hundred fourteen million, five hundred four thousand, four hundred forty".
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