Base | Representation |
---|---|
bin | 110100101011100110… |
… | …0111000001000110001 |
3 | 101211000101002100001001 |
4 | 1221113030320020301 |
5 | 3323143312040103 |
6 | 123545554242001 |
7 | 11113343231101 |
oct | 1512714701061 |
9 | 354011070031 |
10 | 113132143153 |
11 | 43a85166677 |
12 | 19b13886301 |
13 | a88c39a553 |
14 | 5693187201 |
15 | 2e2209001d |
hex | 1a57338231 |
113132143153 has 2 divisors, whose sum is σ = 113132143154. Its totient is φ = 113132143152.
The previous prime is 113132143121. The next prime is 113132143169. The reversal of 113132143153 is 351341231311.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 97598758464 + 15533384689 = 312408^2 + 124633^2 .
It is a cyclic number.
It is not a de Polignac number, because 113132143153 - 25 = 113132143121 is a prime.
It is not a weakly prime, because it can be changed into another prime (113132143183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56566071576 + 56566071577.
It is an arithmetic number, because the mean of its divisors is an integer number (56566071577).
Almost surely, 2113132143153 is an apocalyptic number.
It is an amenable number.
113132143153 is a deficient number, since it is larger than the sum of its proper divisors (1).
113132143153 is an equidigital number, since it uses as much as digits as its factorization.
113132143153 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3240, while the sum is 28.
Adding to 113132143153 its reverse (351341231311), we get a palindrome (464473374464).
The spelling of 113132143153 in words is "one hundred thirteen billion, one hundred thirty-two million, one hundred forty-three thousand, one hundred fifty-three".
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