Base | Representation |
---|---|
bin | 11001101110010010100110… |
… | …100101000010110110111110 |
3 | 112211120100001212002222102210 |
4 | 121232102212211002312332 |
5 | 104312024303211234114 |
6 | 1040340121442001250 |
7 | 32554351130364102 |
oct | 3156224645026676 |
9 | 484510055088383 |
10 | 113132233305534 |
11 | 33058124393553 |
12 | 10831950046226 |
13 | 4b18429598c41 |
14 | 1dd18b4b6d902 |
15 | d12c67db5259 |
hex | 66e4a6942dbe |
113132233305534 has 32 divisors (see below), whose sum is σ = 230394477680640. Its totient is φ = 37027683856800.
The previous prime is 113132233305527. The next prime is 113132233305583. The reversal of 113132233305534 is 435503332231311.
It is a super-3 number, since 3×1131322333055343 (a number of 43 digits) contains 333 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 113132233305492 and 113132233305501.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 659239062 + ... + 659410649.
It is an arithmetic number, because the mean of its divisors is an integer number (7199827427520).
Almost surely, 2113132233305534 is an apocalyptic number.
113132233305534 is an abundant number, since it is smaller than the sum of its proper divisors (117262244375106).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113132233305534 is a wasteful number, since it uses less digits than its factorization.
113132233305534 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1318649976.
The product of its (nonzero) digits is 291600, while the sum is 39.
Adding to 113132233305534 its reverse (435503332231311), we get a palindrome (548635565536845).
The spelling of 113132233305534 in words is "one hundred thirteen trillion, one hundred thirty-two billion, two hundred thirty-three million, three hundred five thousand, five hundred thirty-four".
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