Base | Representation |
---|---|
bin | 1010010010100001000100… |
… | …1111011101011100011011 |
3 | 1111001112102200001000021212 |
4 | 2210220101033131130123 |
5 | 2440324000134414344 |
6 | 40021121052253335 |
7 | 2245232314614545 |
oct | 244502117353433 |
9 | 44045380030255 |
10 | 11313233123099 |
11 | 3671a08187486 |
12 | 13286b6a7124b |
13 | 640aaaa082cb |
14 | 2b17c5da8695 |
15 | 14943a9b879e |
hex | a4a113dd71b |
11313233123099 has 2 divisors, whose sum is σ = 11313233123100. Its totient is φ = 11313233123098.
The previous prime is 11313233123083. The next prime is 11313233123107. The reversal of 11313233123099 is 99032133231311.
It is a happy number.
11313233123099 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11313233123099 - 24 = 11313233123083 is a prime.
It is not a weakly prime, because it can be changed into another prime (11313233123009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656616561549 + 5656616561550.
It is an arithmetic number, because the mean of its divisors is an integer number (5656616561550).
Almost surely, 211313233123099 is an apocalyptic number.
11313233123099 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313233123099 is an equidigital number, since it uses as much as digits as its factorization.
11313233123099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 78732, while the sum is 41.
The spelling of 11313233123099 in words is "eleven trillion, three hundred thirteen billion, two hundred thirty-three million, one hundred twenty-three thousand, ninety-nine".
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