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11313302111 is a prime number
BaseRepresentation
bin10101000100101001…
…10100101001011111
31002012102222021221022
422202110310221133
5141132201131421
65110335154355
7550232324036
oct124224645137
932172867838
1011313302111
114886078361
1222389759bb
1310b3b02007
1479474771d
154633297ab
hex2a2534a5f

11313302111 has 2 divisors, whose sum is σ = 11313302112. Its totient is φ = 11313302110.

The previous prime is 11313302087. The next prime is 11313302153. The reversal of 11313302111 is 11120331311.

11313302111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11313302111 - 214 = 11313285727 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11313302111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11313302911) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656651055 + 5656651056.

It is an arithmetic number, because the mean of its divisors is an integer number (5656651056).

Almost surely, 211313302111 is an apocalyptic number.

11313302111 is a deficient number, since it is larger than the sum of its proper divisors (1).

11313302111 is an equidigital number, since it uses as much as digits as its factorization.

11313302111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11313302111 its reverse (11120331311), we get a palindrome (22433633422).

The spelling of 11313302111 in words is "eleven billion, three hundred thirteen million, three hundred two thousand, one hundred eleven".