Base | Representation |
---|---|
bin | 10101000100101001… |
… | …10101011101101100 |
3 | 1002012102222110112001 |
4 | 22202110311131230 |
5 | 141132201233302 |
6 | 5110335222044 |
7 | 550232336551 |
oct | 124224653554 |
9 | 32172873461 |
10 | 11313305452 |
11 | 488607a919 |
12 | 2238977924 |
13 | 10b3b036a7 |
14 | 794748a28 |
15 | 46332a787 |
hex | 2a253576c |
11313305452 has 48 divisors (see below), whose sum is σ = 21107671200. Its totient is φ = 5287283712.
The previous prime is 11313305441. The next prime is 11313305467. The reversal of 11313305452 is 25450331311.
It is a happy number.
11313305452 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-4 number, since 4×113133054524 (a number of 41 digits) contains 4444 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11313305452.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6952663 + ... + 6954289.
It is an arithmetic number, because the mean of its divisors is an integer number (439743150).
Almost surely, 211313305452 is an apocalyptic number.
It is an amenable number.
11313305452 is a deficient number, since it is larger than the sum of its proper divisors (9794365748).
11313305452 is a wasteful number, since it uses less digits than its factorization.
11313305452 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2290 (or 2288 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 11313305452 its reverse (25450331311), we get a palindrome (36763636763).
The spelling of 11313305452 in words is "eleven billion, three hundred thirteen million, three hundred five thousand, four hundred fifty-two".
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