113133100121 has 2 divisors, whose sum is σ = 113133100122. Its totient is φ = 113133100120.

The previous prime is 113133100079. The next prime is 113133100123. The reversal of 113133100121 is 121001331311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 73259000896 + 39874099225 = 270664^2 + 199685^2 .

It is a cyclic number.

It is not a de Polignac number, because 113133100121 - 2¹⁰ = 113133099097 is a prime.

Together with 113133100123, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 113133100121.

It is not a weakly prime, because it can be changed into another prime (113133100123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56566550060 + 56566550061.

It is an arithmetic number, because the mean of its divisors is an integer number (56566550061).

Almost surely, 2^113133100121 is an apocalyptic number.

It is an amenable number.

113133100121 is a deficient number, since it is larger than the sum of its proper divisors (1).

113133100121 is an equidigital number, since it uses as much as digits as its factorization.

113133100121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 113133100121 its reverse (121001331311), we get a palindrome (234134431432).

The spelling of 113133100121 in words is "one hundred thirteen billion, one hundred thirty-three million, one hundred thousand, one hundred twenty-one".