Base | Representation |
---|---|
bin | 11001101110010011011010… |
… | …111010000100101100110010 |
3 | 112211120102100001002022222002 |
4 | 121232103122322010230302 |
5 | 104312033102433431310 |
6 | 1040340344523014002 |
7 | 32554411650553256 |
oct | 3156233272045462 |
9 | 484512301068862 |
10 | 113133111233330 |
11 | 33058534a0a711 |
12 | 10831b5606a302 |
13 | 4b18539434c46 |
14 | 1dd19595c2266 |
15 | d12cb9ed1da5 |
hex | 66e4dae84b32 |
113133111233330 has 32 divisors (see below), whose sum is σ = 205468469596800. Its totient is φ = 44847931972480.
The previous prime is 113133111233327. The next prime is 113133111233339. The reversal of 113133111233330 is 33332111331311.
It is a junction number, because it is equal to n+sod(n) for n = 113133111233293 and 113133111233302.
It is not an unprimeable number, because it can be changed into a prime (113133111233339) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 68110016 + ... + 69751275.
It is an arithmetic number, because the mean of its divisors is an integer number (6420889674900).
Almost surely, 2113133111233330 is an apocalyptic number.
113133111233330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
113133111233330 is a deficient number, since it is larger than the sum of its proper divisors (92335358363470).
113133111233330 is a wasteful number, since it uses less digits than its factorization.
113133111233330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 137862034.
The product of its (nonzero) digits is 4374, while the sum is 29.
Adding to 113133111233330 its reverse (33332111331311), we get a palindrome (146465222564641).
The spelling of 113133111233330 in words is "one hundred thirteen trillion, one hundred thirty-three billion, one hundred eleven million, two hundred thirty-three thousand, three hundred thirty".
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