Base | Representation |
---|---|
bin | 10101000100101010… |
… | …01100100111110110 |
3 | 1002012110011021122022 |
4 | 22202111030213312 |
5 | 141132212302220 |
6 | 5110341233142 |
7 | 550233213242 |
oct | 124225144766 |
9 | 32173137568 |
10 | 11313400310 |
11 | 4886135113 |
12 | 2238a027b2 |
13 | 10b3b37914 |
14 | 794771422 |
15 | 463348925 |
hex | 2a254c9f6 |
11313400310 has 48 divisors (see below), whose sum is σ = 21345596496. Its totient is φ = 4316900544.
The previous prime is 11313400283. The next prime is 11313400327. The reversal of 11313400310 is 1300431311.
11313400310 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×113134003102 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2097437 + ... + 2102823.
It is an arithmetic number, because the mean of its divisors is an integer number (444699927).
Almost surely, 211313400310 is an apocalyptic number.
11313400310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11313400310 is a deficient number, since it is larger than the sum of its proper divisors (10032196186).
11313400310 is a wasteful number, since it uses less digits than its factorization.
11313400310 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5837 (or 5814 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 11313400310 its reverse (1300431311), we get a palindrome (12613831621).
The spelling of 11313400310 in words is "eleven billion, three hundred thirteen million, four hundred thousand, three hundred ten".
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