Base | Representation |
---|---|
bin | 110100101011101001… |
… | …1111110011100100011 |
3 | 101211000111120212122102 |
4 | 1221113103332130203 |
5 | 3323144301112003 |
6 | 123550102201015 |
7 | 11113365111236 |
oct | 1512723763443 |
9 | 354014525572 |
10 | 113134004003 |
11 | 43a86217769 |
12 | 19b1442316b |
13 | a88c89c547 |
14 | 569350d41d |
15 | 2e2230b588 |
hex | 1a574fe723 |
113134004003 has 2 divisors, whose sum is σ = 113134004004. Its totient is φ = 113134004002.
The previous prime is 113134003993. The next prime is 113134004023. The reversal of 113134004003 is 300400431311.
It is an a-pointer prime, because the next prime (113134004023) can be obtained adding 113134004003 to its sum of digits (20).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113134004003 - 210 = 113134002979 is a prime.
It is not a weakly prime, because it can be changed into another prime (113134004023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56567002001 + 56567002002.
It is an arithmetic number, because the mean of its divisors is an integer number (56567002002).
Almost surely, 2113134004003 is an apocalyptic number.
113134004003 is a deficient number, since it is larger than the sum of its proper divisors (1).
113134004003 is an equidigital number, since it uses as much as digits as its factorization.
113134004003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 113134004003 its reverse (300400431311), we get a palindrome (413534435314).
The spelling of 113134004003 in words is "one hundred thirteen billion, one hundred thirty-four million, four thousand, three".
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