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113134232333141 is a prime number
BaseRepresentation
bin11001101110010100011101…
…101110101110101101010101
3112211120112020011122002210022
4121232110131232232231111
5104312042401434130031
61040341052052034525
732554451513005655
oct3156243556565525
9484515204562708
10113134232333141
1133058a5a826588
1210832209602a45
134b18687792806
141dd1a24454365
15d12d3363497b
hex66e51dbaeb55

113134232333141 has 2 divisors, whose sum is σ = 113134232333142. Its totient is φ = 113134232333140.

The previous prime is 113134232333077. The next prime is 113134232333189. The reversal of 113134232333141 is 141333232431311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 112928346900625 + 205885432516 = 10626775^2 + 453746^2 .

It is a cyclic number.

It is not a de Polignac number, because 113134232333141 - 26 = 113134232333077 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113134232333641) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56567116166570 + 56567116166571.

It is an arithmetic number, because the mean of its divisors is an integer number (56567116166571).

Almost surely, 2113134232333141 is an apocalyptic number.

It is an amenable number.

113134232333141 is a deficient number, since it is larger than the sum of its proper divisors (1).

113134232333141 is an equidigital number, since it uses as much as digits as its factorization.

113134232333141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 46656, while the sum is 35.

Adding to 113134232333141 its reverse (141333232431311), we get a palindrome (254467464764452).

The spelling of 113134232333141 in words is "one hundred thirteen trillion, one hundred thirty-four billion, two hundred thirty-two million, three hundred thirty-three thousand, one hundred forty-one".