1131342410131 has 2 divisors, whose sum is σ = 1131342410132. Its totient is φ = 1131342410130.

The previous prime is 1131342410119. The next prime is 1131342410141. The reversal of 1131342410131 is 1310142431311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1131342410131 - 2¹¹ = 1131342408083 is a prime.

It is a super-2 number, since 2×1131342410131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1131342410096 and 1131342410105.

It is not a weakly prime, because it can be changed into another prime (1131342410111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565671205065 + 565671205066.

It is an arithmetic number, because the mean of its divisors is an integer number (565671205066).

Almost surely, 2^{1131342410131} is an apocalyptic number.

1131342410131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131342410131 is an equidigital number, since it uses as much as digits as its factorization.

1131342410131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 1131342410131 its reverse (1310142431311), we get a palindrome (2441484841442).

The spelling of 1131342410131 in words is "one trillion, one hundred thirty-one billion, three hundred forty-two million, four hundred ten thousand, one hundred thirty-one".