Base | Representation |
---|---|
bin | 10000011101101001110… |
… | …101100010100000001111 |
3 | 11000011012212110111100111 |
4 | 100131221311202200033 |
5 | 122014002110311422 |
6 | 2223422544340451 |
7 | 144510646453213 |
oct | 20355165424017 |
9 | 4004185414314 |
10 | 1131352041487 |
11 | 3a6892807888 |
12 | 16331b614727 |
13 | 828bc2c9a05 |
14 | 3ca872dc943 |
15 | 1e668149a77 |
hex | 10769d6280f |
1131352041487 has 2 divisors, whose sum is σ = 1131352041488. Its totient is φ = 1131352041486.
The previous prime is 1131352041427. The next prime is 1131352041493. The reversal of 1131352041487 is 7841402531311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1131352041487 - 27 = 1131352041359 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131352041427) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565676020743 + 565676020744.
It is an arithmetic number, because the mean of its divisors is an integer number (565676020744).
Almost surely, 21131352041487 is an apocalyptic number.
1131352041487 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131352041487 is an equidigital number, since it uses as much as digits as its factorization.
1131352041487 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80640, while the sum is 40.
Adding to 1131352041487 its reverse (7841402531311), we get a palindrome (8972754572798).
The spelling of 1131352041487 in words is "one trillion, one hundred thirty-one billion, three hundred fifty-two million, forty-one thousand, four hundred eighty-seven".
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