113135431 has 2 divisors, whose sum is σ = 113135432. Its totient is φ = 113135430.

The previous prime is 113135423. The next prime is 113135437. The reversal of 113135431 is 134531311.

It is a strong prime.

It is an emirp because it is prime and its reverse (134531311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113135431 - 2³ = 113135423 is a prime.

It is a super-2 number, since 2×113135431² = 25599251495111522, which contains 22 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113135437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56567715 + 56567716.

It is an arithmetic number, because the mean of its divisors is an integer number (56567716).

Almost surely, 2^113135431 is an apocalyptic number.

113135431 is a deficient number, since it is larger than the sum of its proper divisors (1).

113135431 is an equidigital number, since it uses as much as digits as its factorization.

113135431 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 540, while the sum is 22.

The square root of 113135431 is about 10636.5140436141. The cubic root of 113135431 is about 483.6518781105.

Adding to 113135431 its reverse (134531311), we get a palindrome (247666742).

The spelling of 113135431 in words is "one hundred thirteen million, one hundred thirty-five thousand, four hundred thirty-one".