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1131362017 is a prime number
BaseRepresentation
bin100001101101111…
…0011011011100001
32220211212010220221
41003123303123201
54304112041032
6304133003041
740015263352
oct10333633341
92824763827
101131362017
11530696035
12276a83481
131505118a6
14aa383d29
15694cd597
hex436f36e1

1131362017 has 2 divisors, whose sum is σ = 1131362018. Its totient is φ = 1131362016.

The previous prime is 1131361997. The next prime is 1131362047. The reversal of 1131362017 is 7102631311.

1131362017 is nontrivially palindromic in base 11.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 684293281 + 447068736 = 26159^2 + 21144^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1131362017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1131361982 and 1131362000.

It is not a weakly prime, because it can be changed into another prime (1131362047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565681008 + 565681009.

It is an arithmetic number, because the mean of its divisors is an integer number (565681009).

Almost surely, 21131362017 is an apocalyptic number.

It is an amenable number.

1131362017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131362017 is an equidigital number, since it uses as much as digits as its factorization.

1131362017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 756, while the sum is 25.

The square root of 1131362017 is about 33635.7253080709. The cubic root of 1131362017 is about 1041.9987501873.

Adding to 1131362017 its reverse (7102631311), we get a palindrome (8233993328).

The spelling of 1131362017 in words is "one billion, one hundred thirty-one million, three hundred sixty-two thousand, seventeen".