Base | Representation |
---|---|
bin | 10101000100101100… |
… | …10010000000001101 |
3 | 1002012110200201110121 |
4 | 22202112102000031 |
5 | 141132300400433 |
6 | 5110351304541 |
7 | 550235505616 |
oct | 124226220015 |
9 | 32173621417 |
10 | 11313684493 |
11 | 4886309681 |
12 | 2238b1b151 |
13 | 10b3c07087 |
14 | 794806c0d |
15 | 4633a2c2d |
hex | 2a259200d |
11313684493 has 2 divisors, whose sum is σ = 11313684494. Its totient is φ = 11313684492.
The previous prime is 11313684469. The next prime is 11313684497. The reversal of 11313684493 is 39448631311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10768835529 + 544848964 = 103773^2 + 23342^2 .
It is an emirp because it is prime and its reverse (39448631311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11313684493 - 221 = 11311587341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11313684497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656842246 + 5656842247.
It is an arithmetic number, because the mean of its divisors is an integer number (5656842247).
Almost surely, 211313684493 is an apocalyptic number.
It is an amenable number.
11313684493 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313684493 is an equidigital number, since it uses as much as digits as its factorization.
11313684493 is an evil number, because the sum of its binary digits is even.
The product of its digits is 186624, while the sum is 43.
The spelling of 11313684493 in words is "eleven billion, three hundred thirteen million, six hundred eighty-four thousand, four hundred ninety-three".
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