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113140032000 = 293531722039
BaseRepresentation
bin110100101011110101…
…0111110001000000000
3101211000220221010111120
41221113222332020000
53323202322011000
6123550435312240
711113500255462
oct1512752761000
9354026833446
10113140032000
1143a89664686
1219b1644b680
13a890c001c8
14569423c132
152e22aec6a0
hex1a57abe200

113140032000 has 480 divisors, whose sum is σ = 399787090560. Its totient is φ = 28382003200.

The previous prime is 113140031987. The next prime is 113140032023. The reversal of 113140032000 is 230041311.

It is a tau number, because it is divible by the number of its divisors (480).

It is a super-2 number, since 2×1131400320002 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 55486981 + ... + 55489019.

It is an arithmetic number, because the mean of its divisors is an integer number (832889772).

Almost surely, 2113140032000 is an apocalyptic number.

113140032000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113140032000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (199893545280).

113140032000 is an abundant number, since it is smaller than the sum of its proper divisors (286647058560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113140032000 is an equidigital number, since it uses as much as digits as its factorization.

113140032000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2109 (or 2066 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 113140032000 its reverse (230041311), we get a palindrome (113370073311).

The spelling of 113140032000 in words is "one hundred thirteen billion, one hundred forty million, thirty-two thousand".