Base | Representation |
---|---|
bin | 10101000100101111… |
… | …00001100100101100 |
3 | 1002012111022021112200 |
4 | 22202113201210230 |
5 | 141132341313122 |
6 | 5110402301500 |
7 | 550241334045 |
oct | 124227414454 |
9 | 32174267480 |
10 | 11314010412 |
11 | 4886511531 |
12 | 2239057890 |
13 | 10b3cbc523 |
14 | 79488d8cc |
15 | 4634195ac |
hex | 2a25e192c |
11314010412 has 36 divisors (see below), whose sum is σ = 28991082120. Its totient is φ = 3719673792.
The previous prime is 11314010377. The next prime is 11314010419. The reversal of 11314010412 is 21401041311.
11314010412 is a `hidden beast` number, since 113 + 140 + 1 + 0 + 412 = 666.
It is a tau number, because it is divible by the number of its divisors (36).
It is a Harshad number since it is a multiple of its sum of digits (18).
It is not an unprimeable number, because it can be changed into a prime (11314010419) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2149962 + ... + 2155217.
Almost surely, 211314010412 is an apocalyptic number.
11314010412 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
11314010412 is an abundant number, since it is smaller than the sum of its proper divisors (17677071708).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11314010412 is a wasteful number, since it uses less digits than its factorization.
11314010412 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4305262 (or 4305257 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 18.
Adding to 11314010412 its reverse (21401041311), we get a palindrome (32715051723).
The spelling of 11314010412 in words is "eleven billion, three hundred fourteen million, ten thousand, four hundred twelve".
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