Base | Representation |
---|---|
bin | 10101000100101111… |
… | …00010011110110010 |
3 | 1002012111022110122101 |
4 | 22202113202132302 |
5 | 141132341423010 |
6 | 5110402331014 |
7 | 550241350636 |
oct | 124227423662 |
9 | 32174273571 |
10 | 11314014130 |
11 | 4886514301 |
12 | 2239059a6a |
13 | 10b3cc1123 |
14 | 794890dc6 |
15 | 46341a73a |
hex | 2a25e27b2 |
11314014130 has 32 divisors (see below), whose sum is σ = 20477218608. Its totient is φ = 4500787200.
The previous prime is 11314014121. The next prime is 11314014133. The reversal of 11314014130 is 3141041311.
11314014130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 8 ways, for example, as 420291001 + 10893723129 = 20501^2 + 104373^2 .
It is a junction number, because it is equal to n+sod(n) for n = 11314014098 and 11314014107.
It is not an unprimeable number, because it can be changed into a prime (11314014133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1439010 + ... + 1446850.
Almost surely, 211314014130 is an apocalyptic number.
11314014130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11314014130 is a deficient number, since it is larger than the sum of its proper divisors (9163204478).
11314014130 is a wasteful number, since it uses less digits than its factorization.
11314014130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8622.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 11314014130 its reverse (3141041311), we get a palindrome (14455055441).
The spelling of 11314014130 in words is "eleven billion, three hundred fourteen million, fourteen thousand, one hundred thirty".
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