Base | Representation |
---|---|
bin | 1101011111001… |
… | …10000111001001 |
3 | 21212220010010122 |
4 | 12233212013021 |
5 | 212430441134 |
6 | 15120553025 |
7 | 2542450502 |
oct | 657460711 |
9 | 255803118 |
10 | 113140169 |
11 | 5895697a |
12 | 31a82775 |
13 | 1a59475c |
14 | 11051ba9 |
15 | 9ded02e |
hex | 6be61c9 |
113140169 has 2 divisors, whose sum is σ = 113140170. Its totient is φ = 113140168.
The previous prime is 113140127. The next prime is 113140171. The reversal of 113140169 is 961041311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 112614544 + 525625 = 10612^2 + 725^2 .
It is an emirp because it is prime and its reverse (961041311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113140169 - 212 = 113136073 is a prime.
It is a super-2 number, since 2×1131401692 = 25601395682697122, which contains 22 as substring.
Together with 113140171, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (113140199) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56570084 + 56570085.
It is an arithmetic number, because the mean of its divisors is an integer number (56570085).
Almost surely, 2113140169 is an apocalyptic number.
It is an amenable number.
113140169 is a deficient number, since it is larger than the sum of its proper divisors (1).
113140169 is an equidigital number, since it uses as much as digits as its factorization.
113140169 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 26.
The square root of 113140169 is about 10636.7367646285. The cubic root of 113140169 is about 483.6586296371.
The spelling of 113140169 in words is "one hundred thirteen million, one hundred forty thousand, one hundred sixty-nine".
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