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11314021301134 = 248619311635319
BaseRepresentation
bin1010010010100100000000…
…1110000111101110001110
31111001121110121010121021221
42210221000032013232032
52440332103423114014
640021331205513554
72245260665202646
oct244510016075616
944047417117257
1011314021301134
113672282083292
121328896a128ba
13640ba50ac246
142b185c937526
15149484ca7b24
hexa4a40387b8e

11314021301134 has 8 divisors (see below), whose sum is σ = 16971068316240. Its totient is φ = 5656998529056.

The previous prime is 11314021301117. The next prime is 11314021301179. The reversal of 11314021301134 is 43110312041311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 11314021301099 and 11314021301108.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4845274 + ... + 6790045.

It is an arithmetic number, because the mean of its divisors is an integer number (2121383539530).

Almost surely, 211314021301134 is an apocalyptic number.

11314021301134 is a deficient number, since it is larger than the sum of its proper divisors (5657047015106).

11314021301134 is a wasteful number, since it uses less digits than its factorization.

11314021301134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12121514.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 11314021301134 its reverse (43110312041311), we get a palindrome (54424333342445).

The spelling of 11314021301134 in words is "eleven trillion, three hundred fourteen billion, twenty-one million, three hundred one thousand, one hundred thirty-four".

Divisors: 1 2 486193 972386 11635319 23270638 5657010650567 11314021301134