Base | Representation |
---|---|
bin | 11001101110011010000010… |
… | …101000101000010001011011 |
3 | 112211121002200110212020221221 |
4 | 121232122002220220101123 |
5 | 104312142132332400102 |
6 | 1040343522152512511 |
7 | 32555053062021556 |
oct | 3156320250502133 |
9 | 484532613766857 |
10 | 113140220200027 |
11 | 3306055281a5a9 |
12 | 108333ba9ab737 |
13 | 4b191001a0b07 |
14 | 1dd20317c569d |
15 | d13084172637 |
hex | 66e682a2845b |
113140220200027 has 2 divisors, whose sum is σ = 113140220200028. Its totient is φ = 113140220200026.
The previous prime is 113140220199991. The next prime is 113140220200061. The reversal of 113140220200027 is 720002022041311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113140220200027 - 227 = 113140085982299 is a prime.
It is a super-2 number, since 2×1131402202000272 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 113140220199974 and 113140220200010.
It is not a weakly prime, because it can be changed into another prime (113140220200127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56570110100013 + 56570110100014.
It is an arithmetic number, because the mean of its divisors is an integer number (56570110100014).
Almost surely, 2113140220200027 is an apocalyptic number.
113140220200027 is a deficient number, since it is larger than the sum of its proper divisors (1).
113140220200027 is an equidigital number, since it uses as much as digits as its factorization.
113140220200027 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 113140220200027 its reverse (720002022041311), we get a palindrome (833142242241338).
The spelling of 113140220200027 in words is "one hundred thirteen trillion, one hundred forty billion, two hundred twenty million, two hundred thousand, twenty-seven".
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