Base | Representation |
---|---|
bin | 10101000100101111… |
… | …00101000011000011 |
3 | 1002012111100000001202 |
4 | 22202113211003003 |
5 | 141132342242033 |
6 | 5110402451415 |
7 | 550241423405 |
oct | 124227450303 |
9 | 32174300052 |
10 | 11314024643 |
11 | 4886521199 |
12 | 2239063b6b |
13 | 10b3cc5b4c |
14 | 794894b75 |
15 | 46341d8e8 |
hex | 2a25e50c3 |
11314024643 has 2 divisors, whose sum is σ = 11314024644. Its totient is φ = 11314024642.
The previous prime is 11314024573. The next prime is 11314024669. The reversal of 11314024643 is 34642041311.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11314024643 - 232 = 7019057347 is a prime.
It is a super-2 number, since 2×113140246432 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (11314024693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657012321 + 5657012322.
It is an arithmetic number, because the mean of its divisors is an integer number (5657012322).
Almost surely, 211314024643 is an apocalyptic number.
11314024643 is a deficient number, since it is larger than the sum of its proper divisors (1).
11314024643 is an equidigital number, since it uses as much as digits as its factorization.
11314024643 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 11314024643 its reverse (34642041311), we get a palindrome (45956065954).
The spelling of 11314024643 in words is "eleven billion, three hundred fourteen million, twenty-four thousand, six hundred forty-three".
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