Base | Representation |
---|---|
bin | 10101000100101111… |
… | …00110000000011101 |
3 | 1002012111100012110022 |
4 | 22202113212000131 |
5 | 141132342403243 |
6 | 5110402521525 |
7 | 550241441021 |
oct | 124227460035 |
9 | 32174305408 |
10 | 11314028573 |
11 | 4886524141 |
12 | 22390662a5 |
13 | 10b3cc7883 |
14 | 794896381 |
15 | 46341eb68 |
hex | 2a25e601d |
11314028573 has 2 divisors, whose sum is σ = 11314028574. Its totient is φ = 11314028572.
The previous prime is 11314028567. The next prime is 11314028599. The reversal of 11314028573 is 37582041311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7892012569 + 3422016004 = 88837^2 + 58498^2 .
It is a cyclic number.
It is not a de Polignac number, because 11314028573 - 222 = 11309834269 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11314028503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657014286 + 5657014287.
It is an arithmetic number, because the mean of its divisors is an integer number (5657014287).
Almost surely, 211314028573 is an apocalyptic number.
It is an amenable number.
11314028573 is a deficient number, since it is larger than the sum of its proper divisors (1).
11314028573 is an equidigital number, since it uses as much as digits as its factorization.
11314028573 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20160, while the sum is 35.
Adding to 11314028573 its reverse (37582041311), we get a palindrome (48896069884).
The spelling of 11314028573 in words is "eleven billion, three hundred fourteen million, twenty-eight thousand, five hundred seventy-three".
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