Base | Representation |
---|---|
bin | 10101000100101111… |
… | …00110111001011001 |
3 | 1002012111100101110021 |
4 | 22202113212321121 |
5 | 141132343012332 |
6 | 5110402550441 |
7 | 550241454445 |
oct | 124227467131 |
9 | 32174311407 |
10 | 11314032217 |
11 | 4886526954 |
12 | 2239068421 |
13 | 10b3cc9427 |
14 | 794897825 |
15 | 463420c97 |
hex | 2a25e6e59 |
11314032217 has 2 divisors, whose sum is σ = 11314032218. Its totient is φ = 11314032216.
The previous prime is 11314032209. The next prime is 11314032263. The reversal of 11314032217 is 71223041311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11306281561 + 7750656 = 106331^2 + 2784^2 .
It is an emirp because it is prime and its reverse (71223041311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11314032217 - 23 = 11314032209 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11314032191 and 11314032200.
It is not a weakly prime, because it can be changed into another prime (11314932217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657016108 + 5657016109.
It is an arithmetic number, because the mean of its divisors is an integer number (5657016109).
Almost surely, 211314032217 is an apocalyptic number.
It is an amenable number.
11314032217 is a deficient number, since it is larger than the sum of its proper divisors (1).
11314032217 is an equidigital number, since it uses as much as digits as its factorization.
11314032217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 11314032217 its reverse (71223041311), we get a palindrome (82537073528).
The spelling of 11314032217 in words is "eleven billion, three hundred fourteen million, thirty-two thousand, two hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •