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11314044351120 = 24357197929315313
BaseRepresentation
bin1010010010100100000110…
…0110000011001010010000
31111001121112012111122221010
42210221001212003022100
52440332130323213440
640021333351530520
72245261365134040
oct244510146031220
944047465448833
1011314044351120
113672294097065
1213288a2689a40
13640ba9abc9a4
142b1861a17720
15149486d0c580
hexa4a41983290

11314044351120 has 640 divisors, whose sum is σ = 42876455731200. Its totient is φ = 2410533126144.

The previous prime is 11314044351091. The next prime is 11314044351121. The reversal of 11314044351120 is 2115344041311.

It is a happy number.

It is a super-2 number, since 2×113140443511202 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is not an unprimeable number, because it can be changed into a prime (11314044351121) by changing a digit.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 738844584 + ... + 738859896.

It is an arithmetic number, because the mean of its divisors is an integer number (66994462080).

Almost surely, 211314044351120 is an apocalyptic number.

11314044351120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11314044351120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21438227865600).

11314044351120 is an abundant number, since it is smaller than the sum of its proper divisors (31562411380080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11314044351120 is a wasteful number, since it uses less digits than its factorization.

11314044351120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15727 (or 15721 counting only the distinct ones).

The product of its (nonzero) digits is 5760, while the sum is 30.

Adding to 11314044351120 its reverse (2115344041311), we get a palindrome (13429388392431).

The spelling of 11314044351120 in words is "eleven trillion, three hundred fourteen billion, forty-four million, three hundred fifty-one thousand, one hundred twenty".