11314053433 has 2 divisors, whose sum is σ = 11314053434. Its totient is φ = 11314053432.

The previous prime is 11314053407. The next prime is 11314053449. The reversal of 11314053433 is 33435041311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10474908409 + 839145024 = 102347^2 + 28968^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11314053433 is a prime.

It is not a weakly prime, because it can be changed into another prime (11314053733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657026716 + 5657026717.

It is an arithmetic number, because the mean of its divisors is an integer number (5657026717).

Almost surely, 2^11314053433 is an apocalyptic number.

It is an amenable number.

11314053433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11314053433 is an equidigital number, since it uses as much as digits as its factorization.

11314053433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 11314053433 its reverse (33435041311), we get a palindrome (44749094744).

The spelling of 11314053433 in words is "eleven billion, three hundred fourteen million, fifty-three thousand, four hundred thirty-three".