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11314075605757 is a prime number
BaseRepresentation
bin1010010010100100001101…
…1101010001101011111101
31111001121121101022120020021
42210221003131101223331
52440332211323341012
640021340425452141
72245262224606321
oct244510335215375
944047541276207
1011314075605757
1136722aa7a4141
1213288b1041051
13640bb3413a62
142b1865c31981
15149489933007
hexa4a43751afd

11314075605757 has 2 divisors, whose sum is σ = 11314075605758. Its totient is φ = 11314075605756.

The previous prime is 11314075605751. The next prime is 11314075605769. The reversal of 11314075605757 is 75750657041311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11285124923556 + 28950682201 = 3359334^2 + 170149^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11314075605757 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11314075605751) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657037802878 + 5657037802879.

It is an arithmetic number, because the mean of its divisors is an integer number (5657037802879).

Almost surely, 211314075605757 is an apocalyptic number.

It is an amenable number.

11314075605757 is a deficient number, since it is larger than the sum of its proper divisors (1).

11314075605757 is an equidigital number, since it uses as much as digits as its factorization.

11314075605757 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3087000, while the sum is 52.

The spelling of 11314075605757 in words is "eleven trillion, three hundred fourteen billion, seventy-five million, six hundred five thousand, seven hundred fifty-seven".