113141013134340 has 48 divisors (see below), whose sum is σ = 316836981824832. Its totient is φ = 30166923021696.

The previous prime is 113141013134293. The next prime is 113141013134483. The reversal of 113141013134340 is 43431310141311.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 113141013134298 and 113141013134307.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 124976914 + ... + 125878953.

It is an arithmetic number, because the mean of its divisors is an integer number (6600770454684).

Almost surely, 2^{113141013134340} is an apocalyptic number.

113141013134340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

113141013134340 is an abundant number, since it is smaller than the sum of its proper divisors (203695968690492).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113141013134340 is a wasteful number, since it uses less digits than its factorization.

113141013134340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 250863396 (or 250863394 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 30.

Adding to 113141013134340 its reverse (43431310141311), we get a palindrome (156572323275651).

The spelling of 113141013134340 in words is "one hundred thirteen trillion, one hundred forty-one billion, thirteen million, one hundred thirty-four thousand, three hundred forty".