Base | Representation |
---|---|
bin | 110100101011110111… |
… | …0110001110010101111 |
3 | 101211000222210211120212 |
4 | 1221113232301302233 |
5 | 3323203100430223 |
6 | 123550512533035 |
7 | 11113511613335 |
oct | 1512756616257 |
9 | 354028724525 |
10 | 113141030063 |
11 | 43a8a186526 |
12 | 19b1685117b |
13 | a89118c589 |
14 | 569441bb55 |
15 | 2e22c48278 |
hex | 1a57bb1caf |
113141030063 has 2 divisors, whose sum is σ = 113141030064. Its totient is φ = 113141030062.
The previous prime is 113141030033. The next prime is 113141030111. The reversal of 113141030063 is 360030141311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113141030063 - 218 = 113140767919 is a prime.
It is a super-3 number, since 3×1131410300633 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113141030003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56570515031 + 56570515032.
It is an arithmetic number, because the mean of its divisors is an integer number (56570515032).
Almost surely, 2113141030063 is an apocalyptic number.
113141030063 is a deficient number, since it is larger than the sum of its proper divisors (1).
113141030063 is an equidigital number, since it uses as much as digits as its factorization.
113141030063 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 113141030063 its reverse (360030141311), we get a palindrome (473171171374).
The spelling of 113141030063 in words is "one hundred thirteen billion, one hundred forty-one million, thirty thousand, sixty-three".
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