Base | Representation |
---|---|
bin | 1010010010100100010110… |
… | …1101100110110111010000 |
3 | 1111001121201000111210202011 |
4 | 2210221011231212313100 |
5 | 2440332301020104412 |
6 | 40021344300432304 |
7 | 2245263164320660 |
oct | 244510555466720 |
9 | 44047630453664 |
10 | 11314113441232 |
11 | 367231a096528 |
12 | 1328901848694 |
13 | 640bbb200304 |
14 | 2b186ac801a0 |
15 | 14948ce087a7 |
hex | a4a45b66dd0 |
11314113441232 has 20 divisors (see below), whose sum is σ = 25052679762976. Its totient is φ = 4848905760480.
The previous prime is 11314113441173. The next prime is 11314113441233. The reversal of 11314113441232 is 23214431141311.
It is a super-2 number, since 2×113141134412322 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11314113441194 and 11314113441203.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11314113441233) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50509434894 + ... + 50509435117.
Almost surely, 211314113441232 is an apocalyptic number.
It is an amenable number.
11314113441232 is an abundant number, since it is smaller than the sum of its proper divisors (13738566321744).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11314113441232 is a wasteful number, since it uses less digits than its factorization.
11314113441232 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 101018870026 (or 101018870020 counting only the distinct ones).
The product of its digits is 6912, while the sum is 31.
Adding to 11314113441232 its reverse (23214431141311), we get a palindrome (34528544582543).
The spelling of 11314113441232 in words is "eleven trillion, three hundred fourteen billion, one hundred thirteen million, four hundred forty-one thousand, two hundred thirty-two".
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