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1131414111593 is a prime number
BaseRepresentation
bin10000011101101101100…
…010010100010101101001
311000011101012020222112022
4100131231202110111221
5122014114003032333
62223433042554225
7144512332161503
oct20355542242551
94004335228468
101131414111593
113a6914851a97
12163338368975
13828cc11cc9c
143ca91658d73
151e66d80ac98
hex1076d894569

1131414111593 has 2 divisors, whose sum is σ = 1131414111594. Its totient is φ = 1131414111592.

The previous prime is 1131414111571. The next prime is 1131414111637. The reversal of 1131414111593 is 3951114141311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 758724618304 + 372689493289 = 871048^2 + 610483^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131414111593 - 240 = 31902483817 is a prime.

It is not a weakly prime, because it can be changed into another prime (1131414113593) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565707055796 + 565707055797.

It is an arithmetic number, because the mean of its divisors is an integer number (565707055797).

Almost surely, 21131414111593 is an apocalyptic number.

It is an amenable number.

1131414111593 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131414111593 is an equidigital number, since it uses as much as digits as its factorization.

1131414111593 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6480, while the sum is 35.

The spelling of 1131414111593 in words is "one trillion, one hundred thirty-one billion, four hundred fourteen million, one hundred eleven thousand, five hundred ninety-three".