Base | Representation |
---|---|
bin | 110100101011111001… |
… | …1001000000110110011 |
3 | 101211001001221202100001 |
4 | 1221113303020012303 |
5 | 3323203343420120 |
6 | 123550553210431 |
7 | 11113524402016 |
oct | 1512763100663 |
9 | 354031852301 |
10 | 113142170035 |
11 | 43a8a894a54 |
12 | 19b17100a17 |
13 | a89149b40b |
14 | 569463737d |
15 | 2e22dc0e0a |
hex | 1a57cc81b3 |
113142170035 has 24 divisors (see below), whose sum is σ = 138030071760. Its totient is φ = 89031628224.
The previous prime is 113142170023. The next prime is 113142170111. The reversal of 113142170035 is 530071241311.
It is not a de Polignac number, because 113142170035 - 25 = 113142170003 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113142169985 and 113142170012.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 16987536 + ... + 16994194.
It is an arithmetic number, because the mean of its divisors is an integer number (5751252990).
Almost surely, 2113142170035 is an apocalyptic number.
113142170035 is a deficient number, since it is larger than the sum of its proper divisors (24887901725).
113142170035 is an frugal number, since it uses more digits than its factorization.
113142170035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7555 (or 7488 counting only the distinct ones).
The product of its (nonzero) digits is 2520, while the sum is 28.
The spelling of 113142170035 in words is "one hundred thirteen billion, one hundred forty-two million, one hundred seventy thousand, thirty-five".
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