Base | Representation |
---|---|
bin | 110100101011111001… |
… | …1001000000110100111 |
3 | 101211001001221202022121 |
4 | 1221113303020012213 |
5 | 3323203343420043 |
6 | 123550553210411 |
7 | 11113524402001 |
oct | 1512763100647 |
9 | 354031852277 |
10 | 113142170023 |
11 | 43a8a894a43 |
12 | 19b17100a07 |
13 | a89149b3cc |
14 | 5694637371 |
15 | 2e22dc0ded |
hex | 1a57cc81a7 |
113142170023 has 2 divisors, whose sum is σ = 113142170024. Its totient is φ = 113142170022.
The previous prime is 113142170003. The next prime is 113142170111. The reversal of 113142170023 is 320071241311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113142170023 - 25 = 113142169991 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 113142170023.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113142170003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56571085011 + 56571085012.
It is an arithmetic number, because the mean of its divisors is an integer number (56571085012).
Almost surely, 2113142170023 is an apocalyptic number.
113142170023 is a deficient number, since it is larger than the sum of its proper divisors (1).
113142170023 is an equidigital number, since it uses as much as digits as its factorization.
113142170023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 25.
The spelling of 113142170023 in words is "one hundred thirteen billion, one hundred forty-two million, one hundred seventy thousand, twenty-three".
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